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Q: What is the largest 3 digit number that is divisible by 5 and 13?

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975

-10

No. Consider 13 or 23.

104

A number is divisible by 13 if it is a multiple of 13. In other words, 13 times a number results in a big number that is divisible by 13.

13 and all its multiples are divisible by 13.

There is no answer to this question. No matter what big number one comes up with, it can be multiplied by 13 to make an even bigger number.

Some positive numbers are divisible by 13, but not all of them.

13

-70

The number 70 is divisible by 13, but not evenly.

Starting with 104 (which is 8 x 13), then 117, 130, 143, 156, . . . . , 962, 975, & 988.

936. All numbers divisible by 12 and 13 are multiplies of the lowest common multiple of 12 and 13 which is 156. 999 ÷ 156 = 621/52 ⇒ greatest multiple of 156 not bigger than 999 is 6 x 156 = 936.

-10

No. All multiples of 8 are even, but 141 is odd, so 141 is not divisible by 8. ------------------------------------------ To test if a number is divisible by 8, add 4 times the hundreds digit to 2 times the tens digit to the ones digit; if this sum is divisible by 8, then so is the original number. The test can be repeated on the sum, so continue the summing process until a single digit remains - only if this single digit is an 8 is the original number divisible by 8. 141 → 4 × 1 + 2 × 4 + 1 × 1 = 13 13→ 4 × 0 + 2 × 1 + 3 = 5 5 is not 8, so 141 is not divisible by 8 141 ÷ 8 has a remainder of 5.

14

Every number divisible by 10 is divisible by 5.

No 13 is not divisible by 3 because there would be a remainder of 1 and a number that is divisible by another should have no remainder

All numbers divisible by 5 (of which 15 is a multiple) have a final digit of 0 or 5. All numbers divisible by 3 (of which 15 is a multiple) have the sum of the digits totalling 3 or a multiple of 3. Therefore, a number is divisible by 15 if the sum of its digits total 3 or a multiple of 3 and its final digit is 0 or 5. Example : 32085 ; 3 + 2 + 0 + 8 + 5 = 18 which is divisible by 3. Final digit 5. This number is divisible by 15. (32085 ÷ 15 = 2139) 7420 : 7 + 4 + 2 + 0 = 13. This number is not divisible by 15.

13

First check if it is divisible by 13. You need to delete the last digit from the number, then subtract 9 times the deleted digit from the remaining number. If what is left is divisible by 13, then so is the original number. For example. 195 The last digit is 5 so we delete that. Now 9x5=45 and we must subtract that from 195 So we have 19-45=-26 which is clearly divisible by 13. Now for 11 you need another test. Alternately add and subtract the digits from left to right. (You can think of the first digit as being 'added' to zero.) If the result (including 0) is divisible by 11, the number is also. Example: to see whether 365167484 is divisible by 11, start by subtracting: [0+]3-6+5-1+6-7+4-8+4 = 0; therefore 365167484 is divisible by 11. If your numbers passes both the divisibility tests, for 11 and 13, then it is divisible by both.

Divide the number by thirteen. If the answer comes out even with no remainder, the number is divisible by thirteen.

The number 143 is divisible by 1, 11, 13, and 143.

Add up the digits---5+2+7+8 22 which is NOT a multiple of 3 so it is NOT divisible by 3. == Here is a list of the divisibility rules: 2 If the last digit is even, the number is divisible by 2. 3 If the sum of the digits is divisible by 3, the number is also. 4 If the last two digits form a number divisible by 4, the number is also. 5 If the last digit is a 5 or a 0, the number is divisible by 5. 6 If the number is divisible by both 3 and 2, it is also divisible by 6. 7Take the last digit, double it, and subtract it from the rest of the number;if the answer is divisible by 7 (including 0), then the number is also. 8If the last three digits form a number divisible by 8,then so is the whole number. 9 If the sum of the digits is divisible by 9, the number is also. 10 If the number ends in 0, it is divisible by 10. 11 Alternately add and subtract the digits from left to right. (You can think of the first digit as being 'added' to zero.)If the result (including 0) is divisible by 11, the number is also.Example: to see whether 365167484 is divisible by 11, start by subtracting:[0+]3-6+5-1+6-7+4-8+4 = 0; therefore 365167484 is divisible by 11. 12 If the number is divisible by both 3 and 4, it is also divisible by 12. 13Delete the last digit from the number, then subtract 9 times the deleteddigit from the remaining number. If what is left is divisible by 13,then so is the original number

91 because 13*7=91